Assuming that the array was called A: A.TEMP = CHANGE(A,@FM,@AM) STUFF.YOU.WANT = A.TEMP<1,3>:@VM:A.TEMP<2,3>:@VM:A.TEMP<3,3>
Should work! -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of Barry Brevik Sent: Wednesday, August 18, 2004 13:41 To: U2-users (E-mail) Subject: [U2] [UV] How to return 'column' from dyn array? I just realized that there seems to be no function for the following situation. Given the dynamic array: 10 @vm 20 @vm 30 @FM 11 @vm 21 @vm 31 @FM 12 @vm 22 @vm 32 ...I look at this as the fields being records, or rows, and the values being columns. I'd like a function that returns a dynamic array of just column 3, that is '30', '31' and '32'. Am I making sense? Is there something in UV basic that does this? Barry ------- u2-users mailing list [EMAIL PROTECTED] To unsubscribe please visit http://listserver.u2ug.org/ ------- u2-users mailing list [EMAIL PROTECTED] To unsubscribe please visit http://listserver.u2ug.org/
