Douglas, what are you pulling back? Have you tried creating a simple web
page with your code to ensure that it works as expected?

Rey...

On Thu, Mar 12, 2009 at 6:05 AM, Douglas Nogueira
<[email protected]>wrote:

> I know that.. the request works perfect...
> I changed just to put here...
> The problem is in the response in case of sucess...
>
> 2009/3/12 Blair McBride <[email protected]>
>
>
>> AJAX requests require you to put the protocol in the URL you give it. So
>> you can't just give it "www.site.com" - it needs to be
>> "http://www.site.com";.
>>
>> Hope that helps.
>>
>> - Blair
>>
>>
>>
>>
>> On 12/03/2009 8:29 AM, Douglas Nogueira wrote:
>> > I'm trying to do this:
>> >
>> > jQuery.ajax({
>> > type: "get",
>> > url: "www.site.com <http://www.site.com>",
>> > error: function(msg) {
>> > displayMessage("Problem:" + msg);
>> > },
>> > success: function(response) {
>> > if(response){
>> > if(response=="some")
>> > displayMessage("Address not found!");
>> >                  else
>> > displayMessage("Address found!");
>> >             }
>> >          }
>> >    });
>> >
>> > Doesn't matter what the resposnse is, he dont show anything.
>> >
>> > ---
>> > Doug
>> >
>> > >
>>
>>
>>
>
> >
>

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