Public bug reported:
A program that sets the disposition of a signal to ignore (SIG_IGN) should not
be affected by the ignored signals. However, this is not the case when it calls
sigwait().
Compile and run this program file (sigwait.c):
#include <stdio.h>
#include <signal.h>
int main(int argc, char* argv[]){
struct sigaction sa;
sa.sa_flags = 0;
sa.sa_handler = SIG_IGN;
if (sigaction(SIGHUP,&sa,NULL) < 0){
perror("sigaction error");
return 1;
}
sigset_t mask;
sigemptyset(&mask);
sigaddset(&mask,SIGHUP);
sigprocmask(SIG_BLOCK,&mask,NULL);
int sig = 0;
sigwait(&mask,&sig);
printf("got %d\n",sig);
}
$ gcc sigwait.c
$ ./a.out
Then send it a SIGHUP signal (e.g. kill -HUP pid from another terminal).
The result is:
got 1
I.e. the program, instead of ignoring the signal, is waked up by it.
Apparently, sigwait()
seems to handle an ignored signal as if it was not ignored.
Found in Ubuntu 9.04
** Affects: ubuntu
Importance: Undecided
Status: New
--
sigwait() resumed by ignored signal
https://bugs.launchpad.net/bugs/431813
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