This is correct behaviour. Perhaps these two examples will make it more
clear.
$ OPTIND=1
$ while getopts :a:bc f -a foo -b -c bar; do
> echo "f=$f arg='$OPTARG'"
> done
f=a arg='foo'
f=b arg=''
f=c arg=''
$
$ OPTIND=1
$ while getopts :a:bc f '-a foo -b -c bar'; do
> echo "f=$f arg='$OPTARG'"
> done
f=a arg=' foo -b -c bar'
$
** Changed in: bash (Ubuntu)
Status: New => Invalid
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https://bugs.launchpad.net/bugs/522591
Title:
Bash script getopts strange behaviour
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