Matthias Klose wrote:

> gnu99 is "ISO C99 plus GNU extensions"; please see
> http://gcc.gnu.org/onlinedocs/gcc-4.2.2/gcc/Inline.html: "If you are
> writing a header file to be included in ISO C programs, write __inline__
> instead of inline."

I'm curious. Did you read my big report? If you read it and that was 
your response, I really don't think you understood it.

From:

> https://bugs.launchpad.net/bugs/159923

  #> I am compiling code with "gcc -std=gnu99". According to the gcc
  #> man page, gnu99 means the C99 standard with GNU (ie POSIX) extensions.
  #>
  #> However, compiling something like:
  #>
  #>     inline int plus_2 (int x) { return x + 2 ; }
  #>
  #> results in the warning:
  #>
  #> warning: C99 inline functions are not supported; using GNU89
  #>
  #> I am not using gnu89, I'm using gnu99. This worked for gcc-4.1 and earlier.

If I include include "-std=gnu99" and mention the man page which
states:

    gnu99  : ISO C99 plus GNU extensions.

I read that as meaning that gnu99 is a superset of C99 and hence
there should be no warning whatsoever for valid uses of the "inline"
keyword. Instead I get:

    warning: C99 inline functions are not supported; using GNU89

If gnu99 is a superset of C99 and C99 specifcally supports "inline",
why am I getting that warning for this program:

      inline int plus_2 (int x) { return x + 2 ; }
      int main (void) { return plus_2 (0) ; }

Note, there is no header file involved, just a single C implementation
file, a single standalone program.

Erik
-- 
-----------------------------------------------------------------
Erik de Castro Lopo
-----------------------------------------------------------------
"If you think C++ is not overly complicated, just what is a
protected abstract virtual base pure virtual private destructor
and when was the last time you needed one?" -- Tom Cargill

-- 
gcc-4.2 : regression for -std=gnu99
https://bugs.launchpad.net/bugs/159923
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