From Sergio (for the technical interested):
Just as a data point, the problem is that in a code such as this one:
static force_inline void
memmove_movnt_avx512f(char *dest, const char *src, size_t len, flush_fn flush,
barrier_fn barrier)
{
if ((uintptr_t)dest - (uintptr_t)src >= len)
memmove_movnt_avx512f_fw(dest, src, len, flush);
else
memmove_movnt_avx512f_bw(dest, src, len, flush);
barrier();
VALGRIND_DO_FLUSH(dest, len);
}
you can see that the function received a function pointer called
"barrier", which supposedly is that should get called when "barrier();"
is invoked, but due to (a) "barrier" being also a macro (defined as
'#define barrier() asm volatile("" ::: "memory")'), and (b) the
GCC preprocessor running before the actual compilation phase, we end up
with the code executing the "asm volatile" operation instead of calling
the function pointer provided.
You can reproduce this locally with:
--8<---------------cut here---------------start------------->8---
#include <stdio.h>
#define foo() printf ("Called the macro.\n");
static void
myfoo ()
{
printf ("Called the myfoo function.\n");
}
static void
callfoo (void (*foo) ())
{
foo ();
}
int
main ()
{
callfoo (myfoo);
}
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https://bugs.launchpad.net/bugs/1945694
Title:
Sync 1.11.1-2 for impish
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