Thanks Frank,
my reply inline.
Frank Hofmann wrote:
Well:
The file itself has (filesize / fs_bsize) blocks.
An indirect block of fs_bsize holds fs_bsize/4 block addrs
its because daddr_t is the address datatype and it is of ulong_t basically?
A doubly indirect block of fs_bsize holds fs_bsize/4 direct block addrs
So you need:
(filesize / (fs_bsize^2/4)) indirect blocks
(filesize / (fs_bsize^3/16)) doubly indirect blocks
(filesize / (fs_bsize^4/64)^3) triply indirect blocks
Is the filesize above excluding the size pointed to by direct block?
Isn't it like (if I am not wrong),
no of blocks = (filesize/fs_bsize) + ( (((filesize/fs_bsize) - 12)* 4) /
fs_bsize ) + tripple_indirect blocks ? I am assuming 12 no of indirect
blocks.
Nagaraj.
Typo on the last line of course, the last '^3' shouldn't be there.
FrankH.
If my math serves me right.
And the file is not sparse.
FrankH.
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