On Dec 8, 2008, at 11:19 PM, Wade Preston Shearer wrote:
On 8 Dec 2008, at 23:12, Richard K Miller wrote:
Does this work?
$('tr').hover(banana, banana);
This passes the functions themselves instead of the values that the
functions returned.
Interesting; it does. My problem isn't solved however because in my
real code (my example was simplified), I need to pass values into
the functions like this:
$('tr').hover(banana(a,b), banana(a,b));
You could pass a and b to a function that returns an anonymous
function with the behavior you want:
$('tr').hover(banana_stand(a,b), banana_stand(a,b));
function banana_stand(a, b)
{
return function () { /* do something with a and b */ } // return a
banana(), but it won't be executed until hover() calls for it
}
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