To get it to work (in the meantime):
in your header:
<script
src="//ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js"></script>
then, the entirety of your ajax call is:
$.get('*php_file*'
, function(data)
{
$(my_dvd).html(data);
});
Aaron
On Mar 9, 2011, at 4:05 PM, Merrill Oveson wrote:
> yes, I've tested the php function. It displays on the screen when the
> ajax calls it.
>
> What do you mean caught by the ajax function?
>
> Here's my javascript:
> var url = 'sale_edit_ajax_package_price.php?packageId=' + packageId + '&';
> var answer = getServerText(url,'a');
> alert ("answer is " + answer);
>
> How do I get answer to receive the result from my php file?
>
> I know I need to learn jQuery. I plan on it. In the meantime, I need
> to get this working.
>
> Thanks
>
> On Wed, Mar 9, 2011 at 4:57 PM, Aaron Luman <[email protected]> wrote:
>> Anything that your pop script echos will be caught by the ajax function.
>> Have you tested the php by itself?
>>
>> Also, if you plan on running any level of interactivity on your site I would
>> suggest that you use something like jQuery as it greatly simplifies stuff
>> like this.
>> On Mar 9, 2011 3:36 PM, "Merrill Oveson" <[email protected]> wrote:
>>> Uphpers:
>>>
>>>> From javascript I launch a php script via ajax.
>>> so far so good.
>>>
>>> the php script produces one single value.
>>>
>>> how do I get this value back to javascript?
>>>
>>> Here's my ajax:
>>>
>>> function getServerText(myurl,div_id) {
>>> var http = getXMLHTTPRequest();
>>> //alert ("php file is " + myurl);
>>> //alert ("div_id is " + div_id);
>>> myRand = parseInt(Math.random()*99999999999999999999999999999);
>>> var modurl = myurl+"rand="+myRand;
>>> http.open("GET", modurl, true);
>>> //alert ("readystate is " + http.readyState);
>>> http.onreadystatechange = function() {
>>> //alert ("div_id is " + div_id);
>>> if (http.readyState == 4) {
>>> if (http.status == 200) {
>>> var mytext = http.responseText;
>>> document.getElementById(div_id).innerHTML = mytext;
>>> }
>>> } else {
>>> //document.getElementById(div_id).innerHTML = 'please wait';
>>> //Remember your actually in the directory that launches
>>> ajax.js not the includes directory!
>>> document.getElementById(div_id).innerHTML = '<img
>>> src="images/anim.gif">';
>>> }
>>> }
>>> http.send(null);
>>> }
>>>
>>>
>>> here's my javascript:
>>>
>>> var answer = getServerText(url,'a');
>>>
>>> //answer ends up undefined.
>>>
>>> php:
>>>
>>> I've tried echo and return - no love.
>>>
>>> Someone suggested JSON. I only have one value so this seems like
>>> overkill. Or do I have to use JSON?
>>> If so, do I create the JSON object in the php, then echo it?
>>>
>>> Is there something wrong with my ajax script?
>>>
>>> Thanks
>>>
>>> Merrill
>>>
>>> _______________________________________________
>>>
>>> UPHPU mailing list
>>> [email protected]
>>> http://uphpu.org/mailman/listinfo/uphpu
>>> IRC: #uphpu on irc.freenode.net
>>
>> _______________________________________________
>>
>> UPHPU mailing list
>> [email protected]
>> http://uphpu.org/mailman/listinfo/uphpu
>> IRC: #uphpu on irc.freenode.net
>>
_______________________________________________
UPHPU mailing list
[email protected]
http://uphpu.org/mailman/listinfo/uphpu
IRC: #uphpu on irc.freenode.net
