Gordon,

The devices we’re using are not the same, nor from the same vendor. One has an 
assigned PID/VID, the other only has a VID (PID is 0x0). iSerialNumber for both 
show 0x0 in IORegistryExplorer. 

So… what I’m hoping is either:
- To find the BSD mount point based on PID/VID, or
- To find PID/VID based on BSD mount point

If I could do either of these, I’d be in business. As it stands, my app can 
find all mount points for modem-type devices, but I have no programmatic way to 
match them to a specific PID/VID.
-Carl


> On Jul 8, 2015, at 12:17 PM, Gordon Rankin <[email protected]> wrote:
> 
> Carl,
> 
> If the devices are identical and they do not have a unique serial number or 
> something differentiating them then the mount point will not be easy to 
> determine.
> 
> We had this problem with USB Audio devices that had the same vid, pid and 
> serial number. We are now shipping all products with unique serial numbers so 
> the devices will be easier to find.
> 
> Thanks,
> Gordon
> 
> On 7/8/15 3:00 PM, [email protected] wrote:
>> Message: 1
>> Date: Tue, 07 Jul 2015 16:15:51 -0700
>> From: Carl Hoefs <[email protected]>
>> To: [email protected]
>> Subject: USB devices and BSD mount points
>> Message-ID:
>>      <[email protected]>
>> Content-Type: text/plain; charset=utf-8
>> 
>> I have a Cocoa app (10.10.4) that needs to connect to two USB devices. For 
>> one device, the system will assign it a BSD mount point like 
>> “/dev/cu.usbmodem431”, and for the other device, “/dev/cu.usbmodem641”. 
>> However, sometimes the number changes, so the 431 will be 471, or the 641 
>> will be 671, etc.
>> 
>> Since the mount point is not fixed, what method can I rely on to determine 
>> which device is which? Will the one device always have an enumeration in the 
>> 400s, and the other in the 600s, or is this a completely arbitrary number? 
>> (It seems not to be arbitrary since the one device always shows up in the 
>> 400s and the other always in the 600s, but this seems like a very fragile 
>> assumption.)
>> 
>> -Carl
> 


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