Also, it seems you can use the julianday function in sqLite, which is embedded
in Livecode.
select julianday('2012-05-08') - julianday('2012-03-12') as day
I have not tested this though.
Bob
On May 8, 2012, at 2:18 PM, Bob Sneidar wrote:
> Not only is it not an integer, even if you strip the modulus, 57 is the wrong
> answer for scenario 2. I suspect it will be wrong for every date prior to
> that. This is where the julian date comes in handy. We really need julian in
> the convert parameters.
>
> If you have access to a mySQL database, you can use this query:
>
> select datediff("2012-05-08","2012-03-12") as days
>
> Bob
>
>
> On May 8, 2012, at 1:32 PM, dfepst...@comcast.net wrote:
>
>>
>>
>>
>> I want to count the number of days between some past date and today.
>>
>> I tried this (using Rev 3.0):
>>
>>
>>
>> on mouseUp
>>
>> put "March 12, 2012" into a
>>
>> convert a to seconds -- LC should understand this as midnight
>>
>> get the date
>>
>> convert it to seconds -- should also be midnight
>>
>> put (it - a)/(24*3600) -- elapsed seconds divided by seconds per day
>>
>> end mouseUp
>>
>>
>>
>> This yields "57", which seems right.
>>
>>
>>
>> But if I change the first line to
>>
>>
>>
>> put "March 11, 2012" into a
>>
>>
>>
>> the result is not an integer:
>>
>> 57.958333
>>
>>
>>
>> Why would that be?
>>
>>
>>
>> David Epstein
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