On 9/15/13 11:03 AM, Dr. Hawkins wrote:
If I have strng containing
A B C<tab>1 2 3
then
set the itemDel to tab
repeat for each item itm in strng
put itm
set the itemDel to space
put item 1 of itm
next repeat
Will put out
A B C
A
For the first iteration, but
1
1
for the second--it takes up parsing from the same point, but with the new
itemdDel
If your second delimiter really is a space, then the simple solution is
to use "word" instead of "item" inside the loop. Otherwise you can just
do a replace like this:
set the itemDel to tab
repeat for each item itm in strng
replace vtab with tab in itm
put item 1 of itm
end repeat
I think in this case it isn't necessary to store itm in a temp variable
since nothing else is done with it, but check.
--
Jacqueline Landman Gay | [email protected]
HyperActive Software | http://www.hyperactivesw.com
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