David,
The numberformat doesn't affect precision. It only affects output as is
shown by
on mouseUp
set the numberformat to "00"
put 0.01*1 into x
set the numberformat to "00.00"
put x*1
end mouseUp
It even only affects the current handler and doesn't affect precision in
calling handlers:
on mouseUp
// default is "0.######"
put a1() into x
put x*1
end mouseUp
function a1
set the numberformat to "00"
return 0.01*1
end a1
The above script returns 0.01 instead of 00.
I don't think LiveCode allows you to adjust the precision as other
languages to with e.g. signed and unsigned integers and floating
precision. You'd have to write special routines for this.
I think there is quite a lot of discussion to find in the archives about
high precision and floating point numbers.
--
Best regards,
Mark Schonewille
Economy-x-Talk Consulting and Software Engineering
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On 6/16/2014 20:13, dfepst...@comcast.net wrote:
I am trying to set the numberFormat so that calculation is precise enough for
the situation. Since I don't know ahead of time how many decimal places will
be used, I wrote a function that I hoped would adjust things as necessary.
But when this function is called with parameters m = 1.09131 and n = .0000001
and k = 1, it returns 1.09131 rather than 1.0913101.
The last couple of lines were added for testing, and the debugger shows that
the numberFormat is being set correctly but that the truncated value is put
into hold.
Can anybody see what is going wrong?
Many thanks.
David Epstein
function preciseEnough m,n,k
-- return the value m + k*n
-- default numberFormat shows up to 6 decimal places
-- If m, n, or k has more than that precision, this function sets the
numberFormat with a margin of safety
-- before returning the answer
put length(m) - offset(".",m) into aPlaces
put length(n) - offset(".",n) into bPlaces
put length(k) - offset(".",k) into cPlaces
put the numberFormat into myString
if max(aPlaces,bPlaces,cPlaces) + 4 > length(myString) then
get myString & "####"
set the numberFormat to it
end if
put the numberFormat into nf
put m + k*n into hold
return hold
end preciseEnough
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