if char -2 to -1 of MNOSE = "$W" should work. LAST doesn't return a numeric value (as far as I can tell) so you can't subtract from it, if you do you get strange results
In addition, the order matters. You're putting the last char first, and the second to last char last (if you were allowed to use last that way) So if it did work, you'd be checking W$ against $W You could do it other ways too of course. You could use (char length(MNOSE) -1 of MNOSE & char length(MNOSE) of mNose) to do the comparison.. Note the -1 is first to keep the characters in order. On Wed, May 10, 2017 at 8:18 AM, Richmond via use-livecode < use-livecode@lists.runrev.com> wrote: > Suppose I have a string a bit like this: > > "and then the gigantic monster bit my mother on the nose $W" > > and I want to check that that string ends with "$W" . . . > > I tried this (pseudo code): > > *if the ((last char) & (last char -1)) of MNOSE = "$W"* > > and it did not work. > > > Richmond. > > _______________________________________________ > use-livecode mailing list > use-livecode@lists.runrev.com > Please visit this url to subscribe, unsubscribe and manage your > subscription preferences: > http://lists.runrev.com/mailman/listinfo/use-livecode > _______________________________________________ use-livecode mailing list use-livecode@lists.runrev.com Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-livecode