Richard,

It sounds to me like you are running into the same basic problems that another user was a while back. I posted the following solution which avoids the errors with locating files on Windows while avoiding disk errors and system dialogs...

-- Snip --

My solution to the same problem is to check for a volume serial number first, then if there is one, check for the file I'm looking for. You can do this with the following function...

function GetVolumeSN pDiskLetter
  local volumeSerialNumber
  -- Supports both "C", "C:" and "C:\" styles
  put char 1 of pDiskLetter & ":" into pDisk
  set the hideConsoleWindows to true
  put shell("dir " & pDisk) into tDirData
get matchText(tDirData,"Volume Serial Number is (.*)\n",volumeSerialNumber)
  if it is true then
    return volumeSerialNumber
  else
    return empty
  end if
end GetVolumeSN

If the function returns a Serial Number, I know a disk is located at that drive letter. I then do my "if there is a file..." stuff. If the function returns nothing (empty) then I know there is no disk in the drive and I don't check it.

This seems to avoid the whole "no disc" error in Windows XP SP2. I don't know about other versions... you'll have to test it out.

-- End Snip --

This function was confirmed to work on Vista. But unless you can specify what errors you are getting, there's not much else I can suggest. Hope that helps.


Derek Bump
Dreamscape Software
http://www.dreamscapesoftware.com

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Richard Miller wrote:
I'm looking for suggestions on how to find out if a specific USB camcorder is attached to a users computer (Windows only), and if it is, which volume identifies it. If the camcorder is attached, there will be a specific directory on it which I can use to help identify it.

Let's say I am looking for a folder called "DCIM" on an attached USB drive. Doing this on Windows Vista causes all kinds of problems.

repeat with i = number of lines of the volumes down to 1
   if there is a folder (line i of the volumes & "/DCIM) then
      put true into foundit
      exit repeat
   end if
end repeat

I'm looking for a better solution.

Thanks.
Richard Miller
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