> Now we'll wait for Sarah R. to come on board and show us how it's really > done!
I think you've already got it, but I couldn't resist this challenge.... :-) >From my DateTime library <http://www.troz.net/Rev/libraries/DateTime.rev.gz> I took the following function: -- daysBetween(date1, [date2]) -- -- Returns the number of days between 2 dates. -- If only one date is specified, it will use the current date for the second. -- The dates must be in English format. -- It doesn't matter whether the most recent date is first or last. -- function daysBetween pDate1, pDate2 if pDate2 is empty then put the short english date into pDate2 if pDate1 is not a date or pDate2 is not a date then return empty convert pDate1 from short english date to dateItems convert pDate2 from short english date to dateItems repeat with i = 4 to 7 put 0 into item i of pDate1 put 0 into item i of pDate2 end repeat convert pDate1 from dateItems to seconds convert pDate2 from dateItems to seconds put abs(pDate1 - pDate2) into tDiff return tDiff / (60 * 60 * 24) end daysBetween This gives you the number of days between a pair of dates, so you can then divide by 365 to get the approximate number of years. I guess there would be extra credit for working out how many leap years were in that period and dividing by 365.xx instead for a more accurate result. BUT, I understand that there are problems with the convert command on Windows systems if the year is < 1970, so this may not work properly in those cases. Cheers, Sarah _______________________________________________ use-revolution mailing list use-revolution@lists.runrev.com Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-revolution