After some deep thought today, I achieved my desired goal by xoring each
individual byte. I could swear I tried this before, but anyhoo it's working
now!
put byte 5 to 12 of tPointData into tEncLat -- read out lats, lons and keys
from 129 bytes of tPointData
put byte 13 to 20 of tPointData into tEncLon
put Byte 127 of tPointData into tKey1 -- get Encryption bytes from
tPointData
put byte 128 of tPointData into tKey2
put byte 129 of tPointData into tKey3
etcetera...
-- decrypt lat
replace byte 4 of tEncLat with numToByte((byteToNum(byte 4 of tEncLat)
bitXor (byteToNum(tKey1)))) in tEncLat
replace byte 5 of tEncLat with numToByte((byteToNum(byte 5 of tEncLat)
bitXor (byteToNum(tKey2)))) in tEncLat
replace byte 6 of tEncLat with numToByte((byteToNum(byte 6 of tEncLat)
bitXor (byteToNum(tKey3)))) in tEncLat
Thanks anyway, I was starting to panic after promising an alpha before
Christmas!!
Regards
Neil
From: "Alex Tweedly" <[email protected]>
To: "How to use Revolution" <[email protected]>
Sent: Wednesday, December 09, 2009 12:04 AM
Subject: Re: bitXor 8 bytes of data
Neil Allan wrote:
Does anyone have a way of doing a "simple" bitwise xor with two 8 byte
signed floating point numbers?
I believe the revTalk bitXor command can only accept non signed
"numbers".
I have tried performing the bitXor byte by byte on the two strings using
the byteToNum() function on each byte individually but the result is
quite different to what one would get banging the hex equivalent of the
string into "calculator" on windows.
Calculator gives me the correct answer. I set it to hex mode then just
type in the 8 bytes of hex, hit xor, type in the other hex string and "="
Any Ideas?
bitXor() will do what you want. Can you show a more complete code
fragment (including the data you used) and we'll see if it's something
about how you're setting the data up ?
Thanks
-- Alex.
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