I don't think you can direct where the button goes, the dictionary says:
Summary: Creates a new object on the current card.
I believe you can get around this by placing a group on your card. Perhaps
with an invisible background, sized to window size. At this point you can:
create button "Fred" in group "Testing" card "One" stack "Test"
On Sun, Nov 14, 2010 at 6:22 PM, Bill Vlahos <[email protected]> wrote:
> Make a new stack called "Test" and label the card "One".
>
> Put a button on the card with the following script:
> on mouseUp
> create button "Fred" in card "One" of stack "Test"
> end mouseUp
>
> The compiler doesn't complain but when I click the button I get this error:
> button "Button": execution error at line 2 (create: error in bad parent or
> background expression), char 1
>
> The following script works:
> on mouseUp
> put the defaultStack into vName -- note whatever the defaultStack is
> set the defaultStack to "Test"
> go to card "One"
> create button "Fred"
> set the defaultStack to vName -- reset the defaultStack to what it was
> before
> end mouseUp
>
> Is there a way to directly create a button on a particular card in a
> particular stack without going to it and doing all this? The stack I want to
> create the button into is data stack that never gets viewed directly. In
> this case it will be data in the custom property of that button.
>
> Thanks,
> Bill Vlahos
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