On Thursday, July 31, 2003, at 07:18 AM, Yves COPPE wrote:
if matchtext(theLine,"(0[1-9]|[12][0-9]|3[01])/(0[1-9]|1[0-2])/([0-9][0- 9])",theDay,TheMonth,TheYear) is true then
Try this: "([ 0][1-9]|[12][0-9]|3[01])/(0[1-9]|1[0-2])/([0-9][0-9])"
This will include the space in theDay and there must be space or zero. This can be enhanced to exclude the space and to allow other situations such as the string starting with a one digit day.
This assumes a two digit year, as the original, so it is picking up only the 20 of 2003. It can be enhanced to work with 4 digit and even to skip over a "20" if needed.
This can also be enhanced to handle a single digit month, also.
Dar Scott
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Dar Scott Consulting http://www.swcp.com/dsc/ Programming Services
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