A follow up for those who are interested.
Some controls can have 2 unique id if "0" is also considered an unique id.
Returning an <id 0> on a <put long id of control x of card y of stack z> was only encountered in stack "revPropertyPalette 1" but....
try this in whatever stack:
put the long id of control id 0 <of whatever stack is open>
or
put the long id of btn id 0 <of whatever stack is open> (if the card contains a button of course)
etc..
For a test on stack "revPropertyPalette 1":
put the long id of button "ItemText" of group "MenuSaveOptions" of group "Save options" of card "revdatabaselinkedmenu" of stack "revPropertyPalette 1"
if the result is:
button id 0 of group id 0 of group id 46116 of card id 46117 of stack "revPropertyPalette 1"
then
go card id 46117 of stack "revPropertyPalette 1"
and try again:
put the long id of button "ItemText" of group "MenuSaveOptions" of group "Save options" of card "revdatabaselinkedmenu" of stack "revPropertyPalette 1"
the result is:
button id 46258 of group id 46257 of group id 46116 of card id 46117 of stack "revPropertyPalette 1"
then try :
put the long name of button id 0 of group id 46257 of group id 46116 of card id 46117 of stack "revPropertyPalette 1"
and
put the long name of button id 0 of group id 0 of group id 46116 of card id 46117 of stack "revPropertyPalette 1"
only
put the long name of button id 46257 of group id 0 of group id 46116 of card id 46117 of stack "revPropertyPalette 1"
will give an error
Whenever an <id 0> is encountered a workaround is needed.
Greetings, WA
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