sez [EMAIL PROTECTED]: >How is this statement wrote in Rev, > >len(right(number, 3) > >this in VB will take the number ex: > >number = "12345678" > >and cut it down to > >number = "678" > >starting at the right and give you the first 3 numbers. > >I need to do this in Rev. > > >I searched "len" and got > >put char (length(it) - 3) to (length(it)) of it into myExtension > >but don't understand what it means. Fortunately, it's simpler than that -- you don't need to worry about the length() function at all! CHar -1 of a string is *always* its *last* character; char -2 of a string, it's next-to-last character; and so on. Like so:
put char -3 to -1 of it into myExtension _______________________________________________ use-revolution mailing list [email protected] http://lists.runrev.com/mailman/listinfo/use-revolution
