On 14 Apr 2005, at 01:49, Ken Ray wrote:
On 4/13/05 2:47 PM, "Trevor DeVore" <[EMAIL PROTECTED]> wrote:
get matchText(pString, "(?s)^[ \t\r\n]+(.*?)[ \t\r\n]+$", tReturnVal)
This will strip leading and trailing whitespace from a multiline
string. But given that you say that word 1 to -1 is that much faster I
am going to switch to that. Those of us still trying to break away
from our previous languages like to complicate things on occasion ;)
Unfortunately neither your nor the "word 1 to -1" solution will take into
account hard spaces (non-breaking spaces) that could be part of the
whitespace on either side of the string. So to fix that, you would need to
use:
get matchText(pWhat, "(?s)^\s+(.*?)\s+$", tReturnVal)
I agree that the "word 1 to -1" solution will do what you want 95+% of the
time, but just wanted to make sure that everyone knew there was at least one
'hole' in that approach in case anyone cared. ;-)
Ken Ray Sons of Thunder Software Web site: http://www.sonsothunder.com/ Email: [EMAIL PROTECTED]
Wow, lots of things happen when sleeping :-).
The matchtext version is soooo much slower (about 30x which makes it for me a no no in an extended repeat loop).
The hard space if any, can be dealt with in a one time replacement by a soft space in the container to parse, out of the repeat loop.
(is the non breaking space numtochar(16)? On the mac this is mostly represented by a non-space character for most fonts (rectangle or down arrow, etc) in rev/mc)
Once it is replaced the following is faster than the regex to strip only the "leading" spaces.
Much faster when used inline in a repeat loop (> 10x faster than the regex replacetext version), less when administered by a function (around 4x faster):
put word 1 to -1 of pString into x
replace x with "," in pString
put x & item 2 of pString into strippedString (or return x & item 2 of pString for the function )
You could put this into a oneliner but this makes it about 2x slower than the above:
return word 1 to -1 of pString & item 2 of (replacetext(pString,word 1 to -1 of pString,","))
but still at least more than 2x faster than the regex replacetext version.
Regards, Wouter
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