On 8/13/05 3:22 PM, "Sivakatirswami" <[EMAIL PROTECTED]> wrote:
> What is the ASCII for a hard space and while the space might be > retained, I do believe even with a a hard space, the empty line(s) > deletion at beginning and end of the entire text chunk would still be > achieved (the original goal) > > right? The ASCII value for a hard space is 202, and unfortunately the answer depends on what you've got in your container. If you have: (CR) (spc)(CR) Test1(CR) Test2(CR) (CR) (spc)(CR) when you do word 1 to -1 you get: Test1(CR) Test2 However, if the container is: (CR) (hardspc)(CR) Test1(CR) Test2(CR) (CR) (hardspc)(CR) when you do word 1 to -1 you get: (hardspc)CR Test1(CR) Test2(CR) (hardspc) This is why I use the regex expression for my "stsTrim" function instead of "word 1 to -1"... it's not as elegant, but it *does* handle all the situations. function stsTrim pWhat local tRetVal get matchText(pWhat, "(?s)^\s*(.*?)\s*$", tRetVal) return tRetVal end stsTrim But if you know for sure that you won't be dealing with hard spaces, "word 1 to -1" is really elegant and easier to use I'd think. Ken Ray Sons of Thunder Software Web site: http://www.sonsothunder.com/ Email: [EMAIL PROTECTED] _______________________________________________ use-revolution mailing list [email protected] Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-revolution
