Mark Wieder wrote:
Jim-
Friday, November 25, 2005, 6:45:22 AM, you wrote:
I think it's simpler than that. (warning - it's Friday morning and the
caffeine hasn't really taken effect yet)
Consider any number in terms of its factors. By definition, factors
come in pairs:
the factors of 15 are 1 x 15, 3 x 5
the factors of 17 are 1 x 17
the factors of 18 are 1 x 18, 2 x 9, 3 x 6
The *only* exceptions to this are perfect squares, unless you want to
count the same factor twice:
the factors of 16 are 1 x 16, 2 x 8, and 4
Therefore, every switch will be toggled an even number of times and
turned off except for the perfect squares.
--
-Mark Wieder
[EMAIL PROTECTED]
Yes, Mark. But I think that is essentially Charles solution. It is
certainly simpler. (But not as rich, IMHO :))
For some reason I didn't get Issue 99 of the Run Rev list. I presume
that is where my alternate approach appears, and what you are
responding to.
Jim
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