correct.
On 3/1/06 12:35 PM, "Mark Smith" <[EMAIL PROTECTED]> wrote: > In this case, we're counting delimiters - not items, so it I'm sure > it should be the number of items -1, unless we have a trailing > delimiter, when the item count and delimiter count are the same, > hence the need for "& null" or testing the last char. > > This is how it seems to work on my setup (rev 2.7, Mac OS X): > > 1,2,3 = 3 items, 2 delimiters > ,1,2,3 = 4 items (one empty), 3 delimiters > 1,2,3, = 3 items, 3 delimiters - Rev doesn't count the implied empy > item at the end. > > > Cheers, > > Mark > > > On 1 Mar 2006, at 20:12, Jim Ault wrote: > >>> Also, shouldn't the count be >>> 'the number of items in textStr -1? >> As I indicated in a previous post, it depends on what you are >> trying to >> count when you use items a measure. >> >> If the last char of a string is the asciiChar, then the number of >> items will >> be one less than the true count, however, if null is appended, the >> count >> will be equal to the true count. > > _______________________________________________ > use-revolution mailing list > [email protected] > Please visit this url to subscribe, unsubscribe and manage your subscription > preferences: > http://lists.runrev.com/mailman/listinfo/use-revolution _______________________________________________ use-revolution mailing list [email protected] Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-revolution
