Thanks!
Todd
On Apr 29, 2006, at 10:43 AM, Mark Smith wrote:
If this is a binary string, it may be possible to simply unencode
it the same way
so:
repeat for each char c in yourString
put numToChar((charToNum(c)) bitXor 90) after newStr
end repeat
--(90 is the decimal representation of hexadecimal 5A)
newStr should now contain the unencoded string.
Hope this helps
--
Todd Geist
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