Hi,

Yes, if the data were 5 x 5 (instead of 512, 512) then all I want is a buffer that contains the data:

0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128, 5 lots of (0,128,0,128 in a line, and 5 lines, making 25 groups of 0,128,0,128)
0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,
0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,
0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,
0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128,0,128

Thanks a lot, I think that should do it! I guess when I have my C head on I find it hard to think in TranScript!

All the Best
Dave

On 13 Feb 2007, at 16:30, Mark Smith wrote:

Dave, could you explain in what you're doing - to my non-C eyes it looks like your'e simply building a 512 * 512 list of bytes of alternating value 0 and 128.

If it's any help, you can do this with <put numToChar(0) & numToChar (128) after tBuffer> the required number of times, but I'm guessing that that is not exactly what you want...

Best,

Mark


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