Hi Dave,
Probably, your file contains actual returns (ASCII 13), which are
translated to linefeeds by Revolution, if the file is read as text.
To make it "easy", linefeed, lf, cr and return all return ASCII 10
rather than ASCII 13. Only crlf contains both a real linefeed and a
real return character. If you want to use an actual carriage return,
use numtochar(13).
If you are parsing lines, you might never get at the linefeed. Syntax
like
put line 1 of myVar
will never include the line delimiter. It is not considered part of
the line.
There are two things you can do. Either read the file as binary data
and search for ASCII 13.
open file myFile for binary read
read from file myFile until EOF
put it into myVar
close file myFile
-- now do whatever you want to do with it
replace numToChar(13) with "%" in myVar
or read the file as text and handle the linefeeds
open file myFile for read
read from file myFile until EOF
put it into myVar
close file myFile
-- now do whatever you want to do with it
replace cr with "%" in myVar
Best regards,
Mark Schonewille
--
Economy-x-Talk Consulting and Software Engineering
http://economy-x-talk.com
http;//www.salery.com
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Op 29-jun-2007, om 17:06 heeft Dave het volgende geschreven:
Hi,
I have a file that has "cr" (0x0D) terminators on each line.
If I have the line in "myLine" and do this:
repeat with myIndex = 1 to the length of myLine
if char myIndex of myLine = cr then
--do something at end of line
end if
end repeat
It never finds the cr. I looked in the file and conformed that the
lines end in a single cr character.
When I did a charToNum() on cr is returns 0x0A which is a lf!!!!!
What gives? How can I find the real cr is a variable?
All the Best
Dave
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