As an alternative "manual" method, you could also do the subtraction
yourself. This is untested, but should work - and gives you total
control over any conversion oddities. Just subtract the individual
parts, and if you get a negative minutes portion, roll off another hour.
set the itemDelimiter to "."
put (item 1 of t1 - item 1 of t2) into item 1 of t3
put (item 2 of t1 - item 2 of t2) into item 2 of t3
if (item 2 of t3 < 0) then
subtract 1 from item 1 of t3
add 60 to item 2 of t3
end if
William,
The easiest way to do time and date math is to convert the times or
dates to seconds, do the calculations, then convert them back to
time or date. So to subtract hours (This is assuming time format
for the system is set properly; U.S. would use colons instead of
dots):
put "16.00" into t1
put "7.30" into t2
convert t1 to seconds
convert t2 to seconds
put t1 - t2 into tDiff
put tDiff div (60*60) into tDiffHours
put tDiff mod (60*60) into tDiffMins
put tDiffHours & "." & tDiffMins into tTimeDiff
This is off the top of my head, not tested. But this approach
should work just fine.
Regards,
Devin
Devin Asay
Humanities Technology and Research Support Center
Brigham Young University
_______________________________________________
use-revolution mailing list
[email protected]
Please visit this url to subscribe, unsubscribe and manage your
subscription preferences:
http://lists.runrev.com/mailman/listinfo/use-revolution
---
Brian Yennie
QLD Learning
_______________________________________________
use-revolution mailing list
[email protected]
Please visit this url to subscribe, unsubscribe and manage your subscription
preferences:
http://lists.runrev.com/mailman/listinfo/use-revolution
