Do you mean I can reuse resultMap(which is namespace aware) and
groupBy not only with 2.2.0 but also 2.1.7?

Best,
Minjae

2006/11/9, [EMAIL PROTECTED]
<[EMAIL PROTECTED]>:
Yes, you can use it.

try

Cordiali saluti/Kind Regards.

Alessandro Allievi

(Embedded image moved to file: pic11091.gif)
www.progesoftware.it
Via Mentore Maggini, 48/50
00143 Roma
Phone +39 06.5042621
Fax +39 06.5042676
mailto: [EMAIL PROTECTED]



             [EMAIL PROTECTED]

             09/11/2006 03.51                                           To
                                       user-java@ibatis.apache.org
                                                                        cc
             Please respond to
             [EMAIL PROTECTED]                                     Subject
                apache.org             Avoiding N+1 Selects(1:M and M:N)
                                       with iBATIS version 2.1.7










I read the explanation about Avoiding N+1 Selects(1:M and M:N) with
2.2.0, but the version I am using now is 2.1.7.

Is there way I can do this job like 2.2.0 by using 2.1.7? Make sense?
English is not my native language, so please understand me. ^___^

<sqlMap namespace="ProductCategory">
...
<resultMap id="categoryResult" class="com.ibatis.example.Category"
groupBy="id">
    <result property="id" column="CAT_ID"/>
    <result property="description" column="CAT_DESCRIPTION"/>
<result property="productList" resultMap="ProductCategory.productResult"/>
</resultMap>

<resultMap id="productResult" class="com.ibatis.example.Product">
    <result property="id" column="PRD_ID"/>
    <result property="description" column="PRD_DESCRIPTION"/>
</resultMap>

<select id="getCategory" parameterClass="int" resultMap="categoryResult">
    select C.CAT_ID, C.CAT_DESCRIPTION, P.PRD_ID, P.PRD_DESCRIPTION
    from CATEGORY C
    left outer join PRODUCT P
    on C.CAT_ID = P.PRD_CAT_ID
    where CAT_ID = #value#
</select>
...
</sqlMap>

The solution above is applied with only 2.2.0, right?
How about 2.1.7? This is my question.

Thanks in advance..
Awaiting your reply soon..

Best,
Minjae



Reply via email to