On Tue, May 17, 2005 at 05:38:21PM +0800, Alex LIU wrote:
> In UML,when do_fork was called,the new process P will be created in UML. Then
> in copy_thread_tt(in fact in start_fork_tramp)the corresponding process Q
> will be created in the host linux. I know the pid of the corresponding host
> process Q is appointed as the extern_pid of the UML process P. But then how
> will the 2 processes do next individually?
They aren't really two processes. But they set up signal handlers, and the
timer, and then go to sleep until that process is scheduled.
> In UML,the function copy_thread_tt call start_fork_tramp, which cloned a
> thread. Once the thread was created it will run the outer_tramp function,in
> which cloned another thread. Once the second thread was created it will run
> the tramp function(fork_tramp or new_thread_proc). In fact the first thread
> is a temp one.it will kill itself later.Then why does UML clone 2 threads in
> copy_thread_tt?
To avoid zombies - the parent process is expected to reap exited children,
but as far as UML is concerned, the parent may not wake up for along time,
leaving the child as a zombie for an arbitrary time.
The two threads are the double-fork trick. The parent of the new process
is the first temporary thread, which exits immediately, leaving the new child
to be inherited by init, which will reap children immediately, eliminating
zombies.
> In UML,when the kernel_thread was called,the UML kernel thread P will be
> created in copy_process. And the corresponding host thread Q will be create
> in copy_thread_tt. Then the host thread Q will run its SIGUSR1 signal handler
> new_thread_handler,which will call run_kernel_thread function and exited at
> last. But I think it should be the UML kernel thread P that call
> run_kernel_thread function, any problems?
P and Q are the same thing, so it makes no sense to say the handler should be
run in one rather than the other.
Jeff
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