>From Paolo Giarrusso - Make a UML/i386 instance running on x86_64 pretend
to be i386 rather than x86_64.
Signed-off-by: Jeff Dike <[EMAIL PROTECTED]>
Index: linux-2.6.12-rc6/arch/um/kernel/user_util.c
===================================================================
--- linux-2.6.12-rc6.orig/arch/um/kernel/user_util.c 2005-08-08
12:32:06.000000000 -0400
+++ linux-2.6.12-rc6/arch/um/kernel/user_util.c 2005-08-12 14:00:34.000000000
-0400
@@ -132,7 +132,12 @@
struct utsname host;
uname(&host);
- strcpy(machine_out, host.machine);
+ /* XXX: crude detection of 32-bit binary. */
+ if (sizeof(long) == 4 && !strcmp(host.machine, "x86_64")) {
+ strcpy(machine_out, "i686");
+ } else {
+ strcpy(machine_out, host.machine);
+ }
}
char host_info[(_UTSNAME_LENGTH + 1) * 4 + _UTSNAME_NODENAME_LENGTH + 1];
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