On Fri, May 30, 2014 at 3:22 AM, Nalli, Sanketh <sanketh.na...@hp.com> wrote: > Hi, > > So I start UML with the cmdline > > ./linux rootfstype=hostfs rw mem=1G init=/bin/bash > > > > When the bash shell comes up, I run my prog : ./my_prog > > > > 6173 pts/8 00:00:00 linux > > 6180 pts/8 00:00:00 linux > > 6181 pts/8 00:00:00 linux > > 6182 pts/8 00:00:00 linux > > 6183 pts/8 00:00:00 linux > > 6188 pts/8 00:00:13 linux > > > > > > The last item in the list with PID is 6188 is my program. > > I can tell because my_prog increments a counter in an infinite loop > > And consumes CPU cycles. It shows up on “top” as the dominant process. > > > > My question: > > 1. /proc/6188/exe is invalid. Why ?? > > I mean, it doesn’t point to anything.
This cannot be. On the host side it will point to the UML binary itself and on the guest side to the executed program image. > Shouldn’t it point to my_prog or something ? > > > > 2. What do the 4 UML processes 6173, 6180, 6181, 6182 do ? (6183 is > /bin/bash whos “exe” symlink is also doesn’t point to anything !!) See enjoymind...@gmail.com's answer. > 3. When a UML process, say my_prog (PID 6188) makes a system call, > where is the system call executed – is it within the addr space of 6173 (the > UML kernel process) or 6188 (my_prog running in UML ??) Within the kernel Process. See arch/um/kernel/skas/syscall.c -- Thanks, //richard ------------------------------------------------------------------------------ Time is money. Stop wasting it! Get your web API in 5 minutes. www.restlet.com/download http://p.sf.net/sfu/restlet _______________________________________________ User-mode-linux-user mailing list User-mode-linux-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/user-mode-linux-user
