问题:flink1.1.36用SQL方式如何设置输出到hive表为upsert模式?
flink:1.13.6 hive:1.1.1 hadoop:2.6.0-cdh5.16.2 纯SQL的方式,使用kafka作为source,中间的转换会有DISTINCT 或者 GROUP 操作,将计算结果sink到hive表,会报下面的错误 doesn't support consuming update changes which is produced by node GroupAggregate(groupBy=[id, user_id, status, EXPR$3] 在网上找了答案,说需要将sink表设置为upsert模式,尝试过按照下列方式创建sink表,创建表能成功,但提交INSERT INTO时还是报错 source表 CREATE TABLE data_2432_5074_model( id STRING, user_id STRING,status STRING ) WITH ( 'connector' = 'kafka', 'topic' = 'person', 'properties.bootstrap.servers' = '192.168.9.116:9092', 'properties.group.id' = 'chinaoly-group', 'scan.startup.mode' = 'latest-offset', 'format' = 'json', 'json.fail-on-missing-field'='false', 'json.ignore-parse-errors'='true' ) sink表 CREATE TABLE output_2432_5076_model_1649226175146( id STRING, user_id STRING, status STRING, my_dt timestamp ) TBLPROPERTIES ( 'streaming-source.enable' = 'true', 'streaming-source.partition.include' = 'all', 'streaming-source.partition-order' = 'create-time', 'sink.partition-commit.watermark-time-zone' = 'Asia/Shanghai', 'sink.partition-commit.policy.kind' = 'metastore,success-file', 'write.upsert.enable' = 'true', 'streaming-source.monitor-interval' = '1 min' ) 计算逻辑 INSERT INTO output_2432_5076_model_1649226175146 SELECT DISTINCT id AS id, user_id AS user_id, status AS status ,proctime() FROM (SELECT * FROM data_2432_5074_model) WHERE status = '1' 万能的官方,能否给我答案,先谢谢了。 799590...@qq.com