The end key you've chosen in the first case occur before any of your data: The key is composed of: row, column family, column qualifier, column visibility, and timestamp. You've selected a key which would include everything up to, and including the column visibility, but the default timestamp it uses (Long.MAX_VALUE) would occur before any of your data (timestamps sort in reverse order to show most recent first). You can view timestamps with -st or --show-timestamps option on your scan command in the shell. Your data likely has a real timestamp (less than Long.MAX_VALUE) and would sort after.
What you probably want is to specify the end key's CF as "cf0\0". On Wed, Oct 14, 2015 at 9:59 AM Lu Qin <[email protected]> wrote: > In my accumulo cluster ,the table has this data: > 0 cf0:cq0 [] v0 > 1 cf1:cq1 [] v1 > > then I use scan to find it like this: > > ranges.add(new Range(new Key(new Text("0"), new Text("cf0")), true, > new Key(new Text("0"), new Text("cf0")), true)); > > but it tell me #results=0. > > If i code like this: > > ranges.add(new Range(new Key(new Text("0"), new Text("cf0")), true, > new Key(new Text("0"), new Text("cf00")), true)); > > it works OK. > > > api show me if I set true ,it will include the start and end key.Why I can > not find the data ? > > Thanks. >
