Hi,
I have a build.xml file in Folder_A
and another build.xml file in Folder_B
When i run both these build files separetely, they get executed
successfully.
But using the below code when i run build.xml file in Folder_B and make a
SUBANT call to target in build.xml file present in Folder_A.
i get Unable to open error.
Build.xml in Folder_B
--------------------------------
<target name="call.Folder_A">
<subant target="compile.mxml" inheritall="false">
<fileset dir="../Folder_A/" includes="build.xml" />
</subant>
</target>
Build.xml in Folder_A has target named "compile.mxml" which performs
compiling process of a mxml file.
I'm not getting FileNotFoundException, its an "Unable to open" Error.
I also tried
<target name="call.Folder_A">
<ant antfile="../Folder_A/build.xml" target="compile.mxml"
inheritall="false" />
</target>
but get the same error.
would appreciate any help.
Thanks,
Sunils
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