Thanks Ed, for the clarifications

Yes you are correct that the apps have to handle repeatable reads and not
the databases themselves when using absolute offsets, but SQL databases do
provide such an option at app's peril!!!

"Slices have a fixed size, this ensures that the the "query" does not
execute for arbitrary lengths of time."

I assume it's because of iterators in read-time, which go over results do
merging/reducing/collating results one-by-one that is not so well suited
for jumping to arbitrary offsets, given the practically huge number of
columns involved, right? Did I understand it correctly?

We are now faced with persisting the page with both first & last-key for
prev/next navigation. The problem gets quickly complex, when there we have
to support multiple pages per user. I just wanted to know, if there any
known work-arounds for this.

--
Ravi

On Thu, Nov 15, 2012 at 9:03 PM, Edward Capriolo <edlinuxg...@gmail.com>wrote:

> There are several reasons. First there is no "absolute offset". The
> rows are sorted by the data. If someone inserts new data between your
> query and this query the rows have changed.
>
> Unless you doing select queries inside a transaction with repeatable
> read and your database supports this the query you mention does not
> really have "absolute offsets " either. The results of the query can
> change between reads.
>
> In cassandra we do not execute large queries (that might results to
> temp tables or whatever) and allow you to page them. Slices have a
> fixed size, this ensures that the the "query" does not execute for
> arbitrary lengths of time.
>
>
> On Thu, Nov 15, 2012 at 6:39 AM, Ravikumar Govindarajan
> <ravikumar.govindara...@gmail.com> wrote:
> > Usually we do a SELECT * FROM .... ORDER BY .... LIMIT 26,25 for
> pagination
> > purpose, but specifying offset is not available for range queries in
> > cassandra.
> >
> > I always have to specify a start-key to achieve this. Are there reasons
> for
> > choosing such an approach rather than providing an absolute offset?
> >
> > --
> > Ravi
>

Reply via email to