Yes it does. Thank you Aaron. Now I realized that the system keyspace uses string as keys, like "Ring" or "ClusterName", and I don't know how to convert these type of keys into UUID. Any idea?
Carlos Pérez Miguel 2013/3/25 aaron morton <aa...@thelastpickle.com> > The best thing to do is start with a look at ByteOrderedPartitoner and > AbstractByteOrderedPartitioner. > > You'll want to create a new TimeUUIDToken extends Token<UUID> and a new > UUIDPartitioner that extends AbstractPartitioner<> > > Usual disclaimer that ordered partitioners cause problems with load > balancing. > > Hope that helps. > > ----------------- > Aaron Morton > Freelance Cassandra Consultant > New Zealand > > @aaronmorton > http://www.thelastpickle.com > > On 25/03/2013, at 1:12 AM, Carlos Pérez Miguel <cperez...@gmail.com> > wrote: > > Hi, > > I store in my system rows where the key is a UUID version1, TimeUUID. I > would like to maintain rows ordered by time. I know that in this case, it > is recomended to use an external CF where column names are UUID ordered by > time. But in my use case this is not possible, so I would like to use a > custom Partitioner in order to do this. If I use ByteOrderedPartitioner > rows are not correctly ordered because of the way a UUID stores the > timestamp. What is needed in order to implement my own Partitioner? > > Thank you. > > Carlos Pérez Miguel > > >
