For a while now the binary distribution as included a tool to calculate tokens:

aarons-MBP-2011:apache-cassandra-1.2.11 aaron$ tools/bin/token-generator 
Token Generator Interactive Mode
--------------------------------

 How many datacenters will participate in this Cassandra cluster? 1
 How many nodes are in datacenter #1? 3

DC #1:
  Node #1:                                        0
  Node #2:   56713727820156410577229101238628035242
  Node #3:  113427455640312821154458202477256070484

Cheers



-----------------
Aaron Morton
New Zealand
@aaronmorton

Co-Founder & Principal Consultant
Apache Cassandra Consulting
http://www.thelastpickle.com

On 2/11/2013, at 3:43 am, Ray Sutton <ray.sut...@gmail.com> wrote:

> Your quotes need to be escaped:
> python -c "num=2; print \"\n\".join([(\"token %d: %d\" %(i,(i*(2**127)/num))) 
> for i in range(0,num)])"
> 
> 
> --
> Ray  //o-o\\
> 
> 
> 
> On Fri, Nov 1, 2013 at 10:36 AM, Peter Sanford <psanf...@nearbuysystems.com> 
> wrote:
> I can't tell you why that one-liner isn't working, but you can try 
> http://www.cassandraring.com for generating balanced tokens.
> 
> 
> On Thu, Oct 31, 2013 at 11:59 PM, Techy Teck <comptechge...@gmail.com> wrote:
> I am trying to setup two node Cassandra Cluster on windows machine. I have 
> basically two windows machine and I was following this datastax tutorial 
> (http://www.datastax.com/2012/01/how-to-setup-and-monitor-a-multi-node-cassandra-cluster-on-windows)
> 
> Whenever I use the below command to get the token number from the above 
> tutorial -
> 
>     python -c "num=2; print ""\n"".join([(""token %d: %d"" 
> %(i,(i*(2**127)/num))) for i in range(0,num)])"
> 
> 
> I always get this error - 
> 
>     C:\Users\username>python -c "num=2; print ""\n"".join([(""token %d: %d"" 
> %(i,(i*(2**127)/num))) for i
>     in range(0,num)])"
>       File "<string>", line 1
>         num=2; print "\n".join([("token %d: %d" %(i,(i*(2**127)/num))) for i 
> in range(0,num)])
>                         ^
>     SyntaxError: invalid syntax
>     
> 
> 
> 

Reply via email to