On 25 Jun 2010, at 10:38, paul womack wrote:
> Scott Wilson wrote:
>> Well after a bit of research I finally found a solution to this problem, and
>> though StringUtils and CharSetUtils play a role, there was still a bit of a
>> gap.
>> Here is the code:
>> private static String normalize(String in, boolean includeWhitespace){
>> if (in == null) return "";
>> String out = "";
>> for (int x=0;x<in.length();x++){
>> String s = in.substring(x, x+1);
>> char ch = s.charAt(0);
>> if (Character.isSpaceChar(ch) || (Character.isWhitespace(ch) &&
>> includeWhitespace)){
>> s = " ";
>> }
>> out = out + s;
>> }
>> out = CharSetUtils.squeeze(out, " ");
>> out = StringUtils.strip(out);
>> return out;
>> }
>> Interestingly enough there is no "normalize unicode white space/space chars"
>> method in any of the libs that I tested (e.g. jdom, dom4j).
>
> Surely a simple regex does it?
>
> Sujit posted:
>> s = s.replaceAll("\\s+", " ");
>> or since you are doing unicode:
>> String s = "This\u0200\u0200is\u0200a\u0200\u0200test";
>> System.out.println("before=" + s);
>> s = s.replaceAll("\u0200+", "\u0200");
>> System.out.println("after=" + s);
>
>
> But (reading the regexp documentation), there's
> \p{javaWhitespace} Equivalent to java.lang.Character.isWhitespace()
>
> which appears to do just what's wanted.
Certainly possible - thanks! If there is also an equivalent for isSpaceChar
then that may cover it.
The current code is here:
https://svn.apache.org/repos/asf/incubator/wookie/trunk/parser/java/src/org/apache/wookie/w3c/util/UnicodeUtils.java
The algorithms it is required to conform to are:
http://www.w3.org/TR/widgets/#rule-for-getting-text-content-with-norma
http://www.w3.org/TR/widgets/#rule-for-getting-a-single-attribute-valu
>
> BugBear
>
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