DRILL-4645: "Regex_replace() function is broken”? I still wonder, the characters you are looking for are those used to format a “columns” column on output. Can you show a couple of lines of your CSV file?
Or, take a look at SELECT * FROM … LIMIT 10 to see if the data is being split into columns, or is somehow using the “columns” column… That aside, the docs don’t state the regex syntax used in the REGEX_REPLACE function. Is it Java regex? If so, then you’d have to format it according to the Java syntax ([1]). So: ‘\[|,|\.|]’ Note that “[“ and “.” are part of the regex syntax, so must be escaped. - Paul [1] https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html > On Jul 26, 2017, at 10:49 PM, Divya Gehlot <divya.htco...@gmail.com> wrote: > > Hi, > I have already set the plugin configuration to extractheader :true . > and I followed the below link > https://drill.apache.org/docs/lesson-2-run-queries-with-ansi-sql/ > > SELECT REGEXP_REPLACE(CAST(`Column1` AS VARCHAR(100)), '[,".]', '') AS > `Col1` FROM > dfs.`installedsoftwares/ApacheDrill/apache-drill-1.10.0.tar/apache-drill-1.10.0/sample-data/sample_data.csv` > > Just extracting column which has special charcaters including the delimeter > as one of the special character gives me empty result set . > > Am I missing something ? > > Appreciate the help. > > Thanks, > Divya >
