The problem is cause by the project() operator. The Java compiler does infer its return type and defaults to Tuple.
You can help the compiler like this: DataSet<Tuple1<String>> ds2 = ds.<Tuple1<String>project(0).distinct(0); 2015-04-17 4:33 GMT-05:00 Flavio Pompermaier <pomperma...@okkam.it>: > I have errors in Eclipse doing something like: > > DataSet<Tuple5<String,String,String,String,String>> ds = .... > DataSet<Tuple1<String>> ds2 = .ds.project(0).distinct(0); > > It says that I have to declare ds2 as a Dataset<Tuple> > > On Fri, Apr 17, 2015 at 11:15 AM, Maximilian Michels <m...@apache.org> > wrote: > >> Hi Flavio, >> >> Do you have an exapmple? The DistinctOperator should return a typed >> output just like all the other operators do. >> >> Best, >> Max >> >> On Fri, Apr 17, 2015 at 10:07 AM, Flavio Pompermaier < >> pomperma...@okkam.it> wrote: >> >>> Hi guys, >>> >>> I'm trying to make (in Java) a project().distinct() but then I cannot >>> create the generated dataset with a typed tuple because the distinct >>> operator returns just an untyped Tuple. >>> Is this an error in the APIs or am I doing something wrong? >>> >>> Best, >>> Flavio >>> >> >> > > >
