On 03/11/2010, at 10:52 PM, richardm wrote:
>
> I have a multi-project build with a flat layout as follows:
>
> - main-build
> build.gradle
> settings.gradle
> - ProjA
> - ProjA1
> - ProjA2
> - ProjB
>
> ProjA contains 2 other projects. Their is a single build file in the
> main-build project. My sub-projects ProjA1 and ProjA2 aren't inheriting any
> properties from ProjA. The example below shows a simple property being set
> in ProjA. If I try to output this in ProjA1 I get an error 'Could not find
> property 'propATest' on project ':projA/projA1''
>
> I've tried setting the path with project(':projA:projA1') rather than
> project(':projA/projA1'), but this doesn't work 'Project with path
> ':projA:projA1' could not be found in root project 'main-build'.
>
> settings.gradle
> includeFlat 'projA', 'projB', 'projA/projA1', 'projA/projA2'
includeFlat() creates a flat project structure. What you're asking for above is
the following hierarchy:
root
+-- projA
+-- projA/projA1
+-- projA/projA2
+-- projB
That is, 'projA/projA1' is not a child of 'projA'. It sounds like you're after
something more like this:
root
+-- projA
| +-- projA1
| +-- projA2
+-- projB
You need to do something like this in your settings script:
// Define the logical project structure
include 'projA', 'projA:projA1', 'projA:projA2', 'projB'
// Specify the project directory for each project
project(':projA').projectDir = new File(settingsDir, '../projA')
project(':projA:projA1').projectDir = new File(settingsDir, '../projA/projA1')
... and so on, you can probably write some code to automate this ...
The above leaves the projectDir for the root project as 'main-build'
Alternatively, you could do something like this in your settings script:
rootProject.projectDir = settingsDir.parentFile
include 'projA', 'projA:projA1', 'projA:projA2', 'projB'
--
Adam Murdoch
Gradle Developer
http://www.gradle.org
CTO, Gradle Inc. - Gradle Training, Support, Consulting
http://www.gradle.biz
