On 18/01/2011, at 12:26 PM, Sean Van Buggenum wrote:

> Hi all,
> 
> sorry for begging for help yet again...
> 
> i'm trying to use the 'onlyIf' functionality I found at:
> http://gradle.org/more_about_tasks.html
> 
> I have a task called 'notify'.
> 
> Apart from setting up this task, I also want this task only to be run
> in the case the 'notify' property has been set to 'true'.
> So, I assumed I could do this:
> 
> 
> notify.onlyIf { getProject().properties['notify']=='true' }

When resolving names in the build script, project properties set with -P take 
precedence over task names. So, if you have a property called 'notify' and a 
task called 'notify', then

notify.onlyIf { ... }

will attempt to call onlyIf() on the value of the property called 'notify'. 
Which fails because that value is a String.

Instead, you might do:

tasks.notify.onlyIf { ... }

Or give the property a different name.


> 
> Yet, I get an error:
> 
> * What went wrong:
> A problem occurred evaluating root project 'scripts'.
> Cause: No signature of method: java.lang.String.onlyIf() is applicable
> for argument types:
> (build_gradle_1467b47dd8b3e85829e88798cc56eeb0$_run_closure10) values:
> [build_gradle_1467b47dd8b3
> Possible solutions: notify(), any(), split(), any(groovy.lang.Closure)
> 
> 
> I also tried the exact same example as shown on the webpage, just in
> case I couldn't use the syntax i'd used....
> that also failed in the same way.
> 
> Any idea?
> 
> version shows this:
> 
> D:\dev\scripts>gradle -version
> 
> ----------------------------------------------------------
> Gradle 0.9
> ----------------------------------------------------------
> 
> Gradle build time: Sunday, 19 December 2010 1:42:19 PM EST
> Groovy: 1.7.6
> Ant: Apache Ant version 1.8.1 compiled on April 30 2010
> Ivy: 2.2.0
> JVM: 1.6.0_18 (Sun Microsystems Inc. 16.0-b13)
> OS: Windows XP 5.1 x86
> 
> thanks in advance!
> 
> sean
> 
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--
Adam Murdoch
Gradle Developer
http://www.gradle.org
CTO, Gradle Inc. - Gradle Training, Support, Consulting
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