I've located a part of client code that defines what key-combination to watch
for in guacamole/app/client/controllers/clientController.js
var SHIFT_KEYS = {0xFFE1 : true, 0xFFE2 : true},
ALT_KEYS = {0xFFE9 : true, 0xFFEA : true, 0xFE03 : true,
0xFFE7 : true, 0xFFE8 : true},
CTRL_KEYS = {0xFFE3 : true, 0xFFE4 : true},
MENU_KEYS = angular.extend({}, SHIFT_KEYS, ALT_KEYS, CTRL_KEYS);
I've modified it like this to react on CTRL+ALT+SHIFT+F12:
var SHIFT_KEYS = {0xFFE1 : true, 0xFFE2 : true},
ALT_KEYS = {0xFFE9 : true, 0xFFEA : true, 0xFE03 : true,
0xFFE7 : true, 0xFFE8 : true},
CTRL_KEYS = {0xFFE3 : true, 0xFFE4 : true},
ACTION_KEY = {0xFFC9 : true},
MENU_KEYS = angular.extend({}, SHIFT_KEYS, ALT_KEYS, CTRL_KEYS,
ACTION_KEY);
I've found the 0xFFC9 keycode for F12 here:
https://guacamole.apache.org/doc/guacamole-common-js/Keyboard.js.html
it looks like it won't be that easy - it doesn't work. I restarted the whole
server afterwards, cleared browser offline files and cookies, used a clean
browser I never use: Edge, just to be sure nothing was left in some cache.
It still opened the menu on CTRL+ALT+SHIFT alone.
I need advice.
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