Great! Thank you.
I guess the order for writing and reading the data this way is
important. I mean, for
out.writeUTF("blabla")
out.writeInt(12)
the following would be correct
text = in.readUTF();
number = in.readInt();
and this would fail:
number = in.readInt();
text = in.readUTF();
?
2013/2/27 Sandy Ryza <[email protected]>:
> Hi Paul,
>
> To do this, you need to make your Dog class implement Hadoop's Writable
> interface, so that it can be serialized to and deserialized from bytes.
> http://hadoop.apache.org/docs/r1.1.1/api/org/apache/hadoop/io/Writable.html
>
> The methods you implement would look something like this:
>
> public void write(DataOutput out) {
> out.writeDouble(weight);
> out.writeUTF(name);
> out.writeLong(date.toTimeInMillis());
> }
>
> public void readFields(DataInput in) {
> weight = in.readDouble();
> name = in.readUTF();
> date = new Date(in.readLong());
> }
>
> hope that helps,
> Sandy
>
> On Wed, Feb 27, 2013 at 10:34 AM, Paul van Hoven
> <[email protected]> wrote:
>>
>> The output value in the map function is in most examples for hadoop
>> something like this:
>>
>> public static class Map extends Mapper<LongWritable, Text, outputKey,
>> outputValue>
>>
>> Normally outputValue is something like Text or IntWriteable.
>>
>> I got a custom class with its own properties like
>>
>> public class Dog {
>> string name;
>> Date birthday;
>> double weight;
>> }
>>
>> Now how would I accomplish the following map function:
>>
>> public static class Map extends Mapper<LongWritable, Text, IntWritable,
>> Dog>
>>
>> ?
>
>
