Hi St.Ack: Let say there are 5 versions for a column A with timestamp = [0, 1, 3, 6, 10]. I want to execute an efficient query that returns one version of the column that has a timestamp that is equal to 5 or less. So in this case, it should return the value of the column A with timestamp = 3.
Using the setTimeRange(5, Long.MAX_VALUE) with setMaxVersion = 1, my guess is that it will return the version 6 not version 3. Correct me if I'm wrong. Best Regards, Jerry On Thu, Jul 26, 2012 at 5:13 PM, Stack <[email protected]> wrote: > On Thu, Jul 26, 2012 at 7:43 PM, Jerry Lam <[email protected]> wrote: > > I need some advises on a problem that I'm facing using HBase. How can I > > efficiently query a version of a column when I don't know exactly the > > version I'm looking for? > > For instance, I want to query a column with timestamp that is less or > equal > > to N, if version = N is available, return it to me. Otherwise, I want the > > version that is closest to the version N (order by descending of > > timestamp). That is if version = N - 1 exists, I want it to be returned. > > > > Have you tried a timerange w/ minStamp of N and maxStamp of > HConstants#LATEST_TIMESTAMP Long.MAX_VALUE) returning one version only > (setMaxVersion(1))? > > St.Ack >
