Hi Yogesh
If you are looking for the solution in hive, then the following query will get
you the required result
Select month(Date), max(rate) from date_sample Group BY month(Date);
Regards
Bejoy KS
> From: yogesh.kuma...@wipro.com
> To: user@hive.apache.org
> CC: yogeshdh...@live.com
> Subject: FW: how to perform GROUP BY:: in pig for this
> Date: Sat, 29 Sep 2012 11:22:29 +0000
>
>
>
> Hi all,
>
> I have this data, having fields (Date, symbol, rate)
>
> and I want it to be group by Months, and to find out the maximum rate value
> for each month.
>
> like: for month (08, 36.3), (09, 36.4), (10, 36.8), (11, 37.5) ..
>
>
> (2009-08-21,CLI,33.38)
> (2009-08-24,CLI,33.03)
> (2009-08-25,CLI,33.16)
> (2009-08-26,CLI,32.78)
> (2009-08-27,CLI,32.79)
> (2009-08-28,CLI,33.37)
> (2009-08-31,CLI,32.51)
> (2009-09-11,CLI,34.08)
> (2009-09-14,CLI,35.19)
> (2009-09-15,CLI,35.82)
> (2009-09-16,CLI,36.58)
> (2009-09-17,CLI,37.63)
> (2009-09-18,CLI,37.26)
> (2009-09-21,CLI,36.31)
> (2009-09-22,CLI,35.88)
> (2009-09-23,CLI,35.84)
> (2009-09-24,CLI,33.98)
> (2009-09-25,CLI,32.44)
> (2009-09-28,CLI,33.34)
> (2009-09-29,CLI,33.6)
> (2009-09-30,CLI,33.24)
> (2009-10-01,CLI,31.98)
> (2009-10-02,CLI,31.21)
> (2009-10-05,CLI,31.31)
> (2009-10-21,CLI,32.86)
> (2009-10-26,CLI,33.15)
> (2009-10-27,CLI,32.71)
> (2009-10-28,CLI,32.03)
> (2009-10-29,CLI,32.05)
> (2009-10-30,CLI,31.88)
> (2009-11-02,CLI,31.88)
> (2009-11-03,CLI,31.16)
> (2009-11-04,CLI,31.47)
> (2009-11-09,CLI,31.59)
> (2009-11-25,CLI,30.58)
> (2009-11-27,CLI,30.19)
> (2009-11-30,CLI,30.86)
> (2009-12-01,CLI,31.74)
> (2009-12-02,CLI,32.62)
> (2009-12-03,CLI,33.43)
> (2009-12-04,CLI,34.12)
> (2009-12-07,CLI,33.77)
> (2009-12-08,CLI,33.8)
> (2009-12-09,CLI,33.71)
>
> Please help and suggest .
>
> Thanks & Regards
> Yogesh Kumar
>
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