Re: Easily creating contribution of services

[Achim Hügen]

You could use the object translator and the "instance" ObjectProvider:
<attribute name="service" translator="object" />

<contribution configuration-id="serviceconfig">
        <service id="a" service="instance:service.ServiceAImpl" />
        <service id="b" service="instance:service.ServiceBImpl" />
</contribution>

ServiceAImpl and ServiceBImpl must define a no arguments constructor.

Achim



Am Tue, 19 Dec 2006 23:05:09 +0100 schrieb kristian marinkovic  
<[EMAIL PROTECTED]>:

hi,

is it possible to easily create a contribution with services
without actually defining the service explicitly :)
I currently ended up coding something like the xml snippet
below because i want the IReference injected into
ServiceAImpl and ServiceBImpl. Is there a way of applying
Dependency Injection on object created withing <rules>?

g,
kris

    <service-point id="ref" interface="service.IReference">
        <invoke-factory>
            <construct class="service.Reference" />
        </invoke-factory>
    </service-point>

    <service-point id="service_a" interface="service.IServiceA">
        <invoke-factory>
            <construct class="service.ServiceAImpl"/>
        </invoke-factory>
    </service-point>

    <service-point id="service_b" interface="service.IServiceB">
        <invoke-factory>
            <construct class="service.ServiceBImpl"/>
        </invoke-factory>
    </service-point>

    <schema id="services">
        <element name="service" key-attribute="id">
            <attribute name="id"/>
            <attribute name="service" translator="service" />
            <rules>
                <push-attribute attribute="service" />
                <invoke-parent method="addElement" />
            </rules>
        </element>
    </schema>

<configuration-point id="serviceconfig" schema-id="services" />

<contribution configuration-id="serviceconfig">
        <service id="a" service="service_a" />
        <service id="b" service="service_b" />
</contribution>