I was expecting to get the highest ranked service based on what's
available..

On Wed, May 27, 2015, 12:02 Achim Nierbeck <[email protected]> wrote:

> I'm not sure I follow, what you expect to happen. It works as designed.
> Service Ranking is only used for resolving the services. If the Service is
> bound, no need to do a rewiring.
> How do you get a hold of the service? Are you using a ServiceTracker?
> In case of a Service Tracker you can react on new services and make sure
> you'll pick the one with the highest service rank yourself.
> Another possibility is to use DS and configure it accordingly, to actually
> rewire in case of a new Service with a higher ranking is available.
>
> regards, Achim
>
>
> 2015-05-27 11:57 GMT+02:00 nino martinez wael <
> [email protected]>:
>
>> No ideas?
>>
>> On Wed, May 20, 2015 at 2:01 PM, nino martinez wael
>> <[email protected]> wrote:
>> > Hi
>> >
>> > Are there any way to specify service loading so that the highest
>> > available ranked service will always be used no matter which state the
>> > bundle are in, currently it only loads the highest available service
>> > on load of the bundle.
>> >
>> > This means if I have 3 bundles, A,B and C. C uses either A or B. B are
>> > ranked 2 and A are ranked 1.
>> >
>> > If I go ahead and start karaf load bundle A,B and then C. C will be
>> > refering to B. If I stop B, C then points to A. If I then start B,
>> > bundle C still points to A. When bundle B are started I want bundle C
>> > to point to automatically pickup service B.
>> >
>> > How can I achieve this?
>> >
>> > --
>> > Best regards / Med venlig hilsen
>> > Nino Martinez
>>
>>
>>
>> --
>> Best regards / Med venlig hilsen
>> Nino Martinez
>>
>
>
>
> --
>
> Apache Member
> Apache Karaf <http://karaf.apache.org/> Committer & PMC
> OPS4J Pax Web <http://wiki.ops4j.org/display/paxweb/Pax+Web/> Committer &
> Project Lead
> blog <http://notizblog.nierbeck.de/>
> Co-Author of Apache Karaf Cookbook <http://bit.ly/1ps9rkS>
>
> Software Architect / Project Manager / Scrum Master
>
>

Reply via email to